Multi Choice Problems…

Question 1 of 200.0/ 5.0 PointsThe finite sequence whose general term is an = 0.17n2 – 1.02n + 6.67 where n = 1, 2, 3, …, 9 models the total operating costs, in millions of dollars, for a company from 1991 through 1999.FindA. \$21.58 millionB. \$27.4 millionC. \$23.28 millionD. \$29.1 millionQuestion 2 of 205.0/ 5.0 PointsUse the formula for the sum of the first n terms of a geometric sequence to solve. Find the sum of the first 8 terms of the geometric sequence: -8, -16, -32, -64, -128, . . . .A. -2003B. -2040C. -2060D. -2038Question 3 of 205.0/ 5.0 PointsFind the probability. What is the probability that a card drawn from a deck of 52 cards is not a 10?A. 12/13B. 9/10C. 1/13D. 1/10Question 4 of 200.0/ 5.0 PointsFind the common difference for the arithmetic sequence. 6, 11, 16, 21, . . .A. -15B. -5C. 5D. 15Question 5 of 200.0/ 5.0 PointsFind the indicated sum.A. 28B. 16C. 70D. 54Question 6 of 200.0/ 5.0 PointsEvaluate the expression.1 -A.B.C.D.Question 7 of 200.0/ 5.0 PointsFind the sum of the infinite geometric series, if it exists. 4 – 1 + – + . . .A. – 1B. 3C.D. does not existQuestion 8 of 200.0/ 5.0 PointsFind the probability. One digit from the number 3,151,221 is written on each of seven cards. What is the probability of drawing a card that shows 3, 1, or 5?A. 5/7B. 2/7C. 4/7D. 3/7Question 9 of 200.0/ 5.0 PointsA game spinner has regions that are numbered 1 through 9. If the spinner is used twice, what is the probability that the first number is a 3 and the second is a 6?A. 1/18B. 1/81C. 1/9D. 2/3Question 10 of 205.0/ 5.0 PointsUse the formula for the sum of the first n terms of a geometric sequence to solve. Find the sum of the first four terms of the geometric sequence: 2, 10, 50, . . . .A. 312B. 62C. 156D. 19Question 11 of 200.0/ 5.0 PointsWrite a formula for the general term (the nth term) of the geometric sequence., – , , -, . . .A. an = n – 1B. an = –  (n – 1)C. an = n – 1D. an = n – 1Question 12 of 205.0/ 5.0 PointsDoes the problem involve permutations or combinations? Do not solve. In a student government election, 7 seniors, 2 juniors, and 3 sophomores are running for election. Students elect four at-large senators. In how many ways can this be done?A. permutationsB. combinationsQuestion 13 of 205.0/ 5.0 PointsSolve the problem. Round to the nearest hundredth of a percent if needed. During clinical trials of a new drug intended to reduce the risk of heart attack, the following data indicate the occurrence of adverse reactions among 1100 adult male trial members. What is the probability that an adult male using the drug will experience nausea?A. 2.02%B. 1.73%C. 27.59%D. 2.18%Question 14 of 200.0/ 5.0 PointsThe general term of a sequence is given. Determine whether the given sequence is arithmetic, geometric, or neither. If the sequence is arithmetic, find the common difference; if it is geometric, find the common ratio. an= 4n – 2A. arithmetic, d = -2B. geometric, r = 4C. arithmetic, d = 4D. neitherQuestion 15 of 205.0/ 5.0 PointsEvaluate the factorial expression.A. n + 4!B. 4!C. (n + 3)!D. 1Question 16 of 205.0/ 5.0 PointsIf the given sequence is a geometric sequence, find the common ratio., , , ,A.B. 30C.D. 4Question 17 of 205.0/ 5.0 PointsSolve the problem. Round to the nearest dollar if needed. Looking ahead to retirement, you sign up for automatic savings in a fixed-income 401K plan that pays 5% per year compounded annually. You plan to invest \$3500 at the end of each year for the next 15 years. How much will your account have in it at the end of 15 years?A. \$77,295B. \$75,525C. \$76,823D. \$73,982Question 18 of 200.0/ 5.0 PointsFind the term indicated in the expansion.(x – 3y)11; 8th termA. -721,710x7y4B. -721,710x4y7C. 240,570x7y4D. 240,570x4y8Question 19 of 200.0/ 5.0 PointsFind the probability. Two 6-sided dice are rolled. What is the probability that the sum of the two numbers on the dice will be greater than 10?A. 1/12B. 5/18C. 3D. 1/18Question 20 of 205.0/ 5.0 PointsDoes the problem involve permutations or combinations? Do not solve. A club elects a president, vice-president, and secretary-treasurer. How many sets of officers are possible if there are 15 members and any member can be elected to each position? No person can hold more than one office.A. permutationsB. combinations