Stats homework help

Question 1 of 171.0 PointsA researcher hypothesizes that the variation in the amount of money spent on business dinners is greater than the variation of the amount of money spent on lunches. The variance of nine business dinners was $6.12 and the variance of 12 business lunches was $0.87. What is the test value?Reset SelectionQuestion 2 of 171.0 PointsAn investor wants to compare the risks associated with two different stocks. One way to measure the risk of a given stock is to measure the variation in the stock’s daily price changes.In an effort to test the claim that the variance in the daily stock price changes for stock 1 is different from the variance in the daily stock price changes for stock 2, the investor obtains a random sample of 21 daily price changes for stock 1 and 21 daily price changes for stock 2.The summary statistics associated with these samples are: n1 = 21, s1 = .725, n2 = 21, s2 = .529.If you compute the test value by placing the larger variance in the numerator, at the .05 level of significance, would you conclude that the risks associated with these two stocks are different?Reset SelectionQuestion 3 of 171.0 PointsWhich of the following statements is true regarding the F – distribution?Reset SelectionPart 2 of 8 -Question 4 of 171.0 PointsThe marketing manager of a large supermarket chain would like to use shelf space to predict the sales of pet food. For a random sample of 12 similar stores, she gathered the following information regarding the shelf space, in feet, devoted to pet food and the weekly sales in hundreds of dollars.Store123456Shelf Space555101010Weekly Sales1. Space151515202020Weekly Sales2. is the estimated regression equation?Reset SelectionQuestion 5 of 171.0 PointsThe standard error of the estimate, sest, is essentially theReset SelectionQuestion 6 of 171.0 PointsThe correlation value ranges fromReset SelectionQuestion 7 of 171.0 PointsIn a simple linear regression analysis, the following sum of squares are produced:= 500= 100= 400The proportion of the variation in Y that is explained by the variation in X is:Reset SelectionQuestion 8 of 171.0 PointsIf an estimated regression line has a Y-intercept of –7.5 and a slope of 2.5, then when X = 3, the actual value of Y is:Reset SelectionPart 3 of 8 -Question 9 of 172.0 PointsAccepted characters: numbers, decimal point markers (period or comma), sign indicators (-), spaces (e.g., as thousands separator, 5 000), “E” or “e” (used in scientific notation). NOTE: For scientific notation, a period MUST be used as the decimal point marker.Complex numbers should be in the form (a + bi) where “a” and “b” need to have explicitly stated values.For example: {1+1i} is valid whereas {1+i} is not. {0+9i} is valid whereas {9i} is not.A business major wants to determine whether the variation in advertising costs of hair salons is different from the variation in advertising costs of nail salons.  He surveys several businesses and finds the standard deviation in monthly advertising costs is $23 for 12 hair salons, and $43 for 8 nail salons.What is the test value for this hypothesis test?Test value:Reset SelectionPart 8 of 8 -Question 16 of 171.0 PointsIf there is no linear relationship between two variables X and Y, the coefficient of determination, R2, must be 1.0.Reset SelectionQuestion 17 of 171.0 PointsIn every regression study there is a single variable that we are trying to explain or predict. This is called the response variable or dependent variable.Reset Selection