# math

You must also respond to 2 classmates. A request for clarification on the procedure used, a suggestion for an alternate method of solving the problem or a general comment about the technique would all be appropriate. I’m sure that a “thank you” for an exceptionally clear explanation would also be welcome!bank teller has 54 \$5 and \$20 bills in her cash drawer. The value of the bills is \$780. How many \$5 bills are there?Let x equal the number of \$5 billsLet y equal the number of \$20 billsWe know that together the number of \$5 bills and the \$20 bills is 54, so that is the first equation.x + y = 54Next the total value of the bills combined is \$780, that is the second equation.5x + 20y = 780Now that we have our two equations we can solve by substitution. To do so we have to rearrange our first equation solving for one of the variablesx + y = 54- x – xy = 54 – xNext we will substitute this equation into the second, and solve.5x + 20(54 – x) = 780 (multiply 20 and 54, and multiply 20 and – x)5x + 1080  20x = 780 (combine 5x and  20x)-15x + 1080 = 780 (subtract 1080 from both sides)-15x = -300 (divide by -15)x = 20Now that we have our x value, we can solve for y using our first equation.20 + y = 54 (subtract 20 from each side)y = 34Finally, to check the answers you substitute them into both of the equations.20 + 34 = 5454 = 54 TRUE5(20) + 20(34) = 780100 + 680 = 780780 = 780 TRUEThe final answer is there are 20 – \$5 bills, and 34 – \$20 bills.What would your response be to this person?The Problem: (x) number of bracelets are sold at \$8 each and (y) number of necklaces at \$11 each. Rosaria paid a total of \$1140. How many bracelets and how many necklaces did she purchase?The Solution:1.) Listed are the known factors:o Let the number of bracelets be represented by the variable: x? In which each x number of bracelets are priced at \$8o Let the number of necklaces be represented by the variable: y? In which each y number of necklaces are priced at \$112.) Listed are the relationships between x and yo x + y = 120o \$8x + \$11y = \$11403.) I will be using both elimination and substitution process to solve this problem.? First I’d use the elimination process to solve the system of equations:o -8[x + y = 120] -8x  8y = -(960) (multiply equation by -8)8x + 11y = 1140 (eliminate x- variable)o \$8x + \$11y = \$1140 3y = 180 (isolate y through division)3 3y = 60 (solve)? Second I’d use the substitution process to solve for the x-variable:o x + y = 120 x + (60) = 120 (substitute known variable: y)x = 60 (simple subtraction to isolate x)o \$8x + \$11y = \$1140 x = 60 (solve)Checking the answers:o x + y = 120 (60) + (60) = 120 (substitute known variables)8(60) + 11(60) = 1140 (Solve)o \$8x + \$11y = \$1140SOLUTION: Rosaria purchased 60 bracelets and 60 necklaces.what will be your response to this person?